Question

Praveen spent 20% of his pocket money on transport and Rs 60 on breakfast. If he spent 15% of the remaining money on his lunch and had Rs 340 left, what was his pocket money?

Answer 1

Step-by-step explanation:

he spent on transport =20%

spent on breakfast =60/-

spent on lunch =15%

remaining amount=340

rs he spent on transport=20/100×340

=68

rs he spent on lunch=15/100×340

=51

total his pocket money=68+51+60+340

=₹519

Answer 2

Given : Praveen spent 20% of his pocket money on transport and Rs 60 on breakfast. He spent 15% of the remaining money on his lunch and had Rs 340 left.

To find : His pocket money.

Solution :

We can simply solve this mathematical problem by using the following mathematical process. (our goal is to calculate his pocket money)

Let, his pocket money = Rs. x

Expenditure on transport :

= x × 20%

$= x \times \frac{20}{100}$

$= Rs. \: \: \frac{x}{5}$

Expenditure on breakfast = Rs. 60

Total expenditure on transport and breakfast :

$= \frac{x}{5} + 60$

$= Rs. \: \: \frac{x+300}{5}$

Remaining money :

$= x - \frac{x + 300}{5}$

$= \frac{5x - x - 300}{5}$

$= Rs. \: \: \frac{4x - 300}{5}$

Expenditure on lunch :

$= \frac{4x - 300}{5} \times 15\%$

$= \frac{4x - 300}{5} \times \frac{15}{100}$

$= Rs. \: \: \frac{12x - 900}{100}$

Remaining money :

$= \frac{4x - 300}{5} - \frac{12x - 900}{100}$

$= \frac{80x - 6000 - 12x + 900}{100}$

$= Rs. \frac{68x - 5100}{100}$

According to the data mentioned in the question,

$\frac{68x - 5100}{100} = 340$

$68x - 5100 = 34000$

$68x = 34000 + 5100$

$68x = 39100$

$x = \frac{39100}{68}$

$x = 575$

His pocket money = Rs. x = Rs. 575

(This will be considered as the final result.)

Hence, his pocket money was Rs. 575