Question

Pravin goes to the football ground to play football. The distance-time graph of his
journey from his home to the ground is given as a figure. (Convert time from
minutes to seconds)

Please answer correctly

Answer 1

Explanation:

1min = 60 sec

60 × 2 = 120s

60 × 4 = 240s

60 × 6 =360s

60 × 8 = 480s

60 × 10 = 600s

60 × 12 = 720s

Answer 2

a)The type of motion observed are:

$i)Between \ O \ to\ A\ motion \ observed\ is\ uniform \ motion.\\ii)Between \ B\ to \ C \ Pravin \ is\ at\ rest.$

b)The average speed of the motion is calculated by :$\frac{Total\ distannce\ traveled}{Total\ time\ taken}$

Given, total distance traveled=$225m$

Total time taken=$12min=12\times 60=720 sec$

Average speed=$\frac{Total\ distannce\ traveled}{Total\ time\ taken}=\frac{225}{720} =0.3125m/s$

Hence, the average speed is 0.3125 m/s.