Pravin has applied a force of 100 N on an object,at an angle of 60° to the horizontal.The object gets displaced in the horizontal direction an 400 J work is done.What is the displacement of the object?(cos 60°=1/2)
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3
Answer:
D = 400÷ 50
Explanation:
W= F*D* COS THETA 400= 100× D× COS 60 , THEREFORE 400= 100× D× 1/2 ,
400/50 .
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0
Explanation:
400÷50
=8
Pravin has applied force is 8 units.
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