Predict in which of the following entropy increases or se decreases
a) 2NaHCO3 - Na2CO3 + CO2 + H2O
Answers
Answer:
Explanation:
JNV Hooghly Great
Predict which of the following entropy increases/decreases :
(a) H₂(g)→2H(g)
(b) 2NaHCO₃(g)→Na₂CO₃(s)+CO₂(g)+H₂O(g)
(c) A liquid crystallizes into a solid.
(d) Temperature of a crystalline solid is raised from 0 K to 115 K.
The increment or decrement of entropy of all of the following are as follows:
a) Increase
b) No change
c) Decrease
d) Decrease
To Find:
The entropy change.
Solution:
In short, entropy defines randomness.
How a system or a surrounding is in continuous motion is expressed through entropy.
Entropy is denoted as ΔS. And to check the entropy of a reaction we need to see the number of moles of gas present after a reaction gets completed.
a) In this reaction as two molecules of hydrogen atoms are getting generated from a hydrogen molecule the randomness increases, so the entropy also increases. (Product has more moles than reactant)
b) Here in this reaction, two gaseous product (one mole each) has been generated from 2 moles of NaHCO₃ which is also a gas.
So, Product - Reactant = 2 - 2
i.e, 0
So, there is no change in entropy.
c) When a liquid gets converted into a solid, the randomness of its molecules gets more into an ordered state making the entropy decrease.
d) Temperature in any sort increases the randomness within any compound, molecule, or element. Here as temperature gets increased, entropy also gets increased.
So the entropy change becomes : a) Increase b) No change c) Decrease d) Decrease
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