Chemistry, asked by arunimatripathi05, 2 months ago

Predict the energy of the 2p electrons in K [k = 13.6 eV and Sze = 2.579 +0.333(2p - 1) - 0.0773(3s) - 0.0161(3p + 4s) - 0.0048(30) + 0.0085(4p)]

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Predict the energy of the 2p electrons in K [k = 13.6 eV and Sze = 2.579 +0.333(2p - 1) - 0.0773(3s) - 0.0161(3p + 4s) - 0.0048(30) + 0.0085(4p)]

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Predict the energy of the 2p electrons in K [k = 13.6 eV and Sze = 2.579 +0.333(2p - 1) - 0.0773(3s) - 0.0161(3p + 4s) - 0.0048(30) + 0.0085(4p)]

Predict the energy of the 2p electrons in K [k = 13.6 eV and Sze = 2.579 +0.333(2p - 1) - 0.0773(3s) - 0.0161(3p + 4s) - 0.0048(30) + 0.0085(4p)

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Answered by geethacn18

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sorry I do not know the ans

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