Preeti has a recurring deposit account of rupees 1000 per month at 10% per annum. If she gets rupees 5550 as interest at the time of maturity, find the total time for which the account was held
Answers
Amount of recurring deposit per month = Rs. 1000 Rate of interest = 10 % p.a. let period = n months Amount of interest = 5550 ................................ (1) Read more on Sarthaks.com - https://www.sarthaks.com/145260/priyanka-has-a-recurring-deposit-account-of-rs-1000-per-month-at-10-per-annum
here is the answer
amount of recurring deposit per month = Rs. 1000
Rate of interest = 10 % p.a.
let period = n months
Amount of interest = 5550
Recurring deposit interest is given by.......(1)
I= P×[n(n+1)/(2×12] (r/100).......(1)
where p is monthly contribution,
p= RS.1000
n= number of months,
r= rate of interest= 10%
and I= interest= Rs.5550
hence by substituting the values in eqn(1) we get
1000×[n(n+1)/24]×(10/100)= 5550 or
n (n+1)=(24/100)×5550= 1332
hence, n2+n-1332= (n+37) (n-36)=0
hence number of months=36
n=36
it means 3 years
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