Math, asked by parinitaprashar19iro, 9 months ago

Preeti has a recurring deposit account of rupees 1000 per month at 10% per annum. If she gets rupees 5550 as interest at the time of maturity, find the total time for which the account was held

Answers

Answered by SankuS
14

Amount of recurring deposit per month = Rs. 1000 Rate of interest = 10 % p.a. let period = n months Amount of interest = 5550 ................................ (1) Read more on Sarthaks.com - https://www.sarthaks.com/145260/priyanka-has-a-recurring-deposit-account-of-rs-1000-per-month-at-10-per-annum

Answered by rahul077
82

here is the answer

amount of recurring deposit per month = Rs. 1000

Rate of interest = 10 % p.a.

let period = n months

Amount of interest = 5550

Recurring deposit interest is given by.......(1)

I= P×[n(n+1)/(2×12] (r/100).......(1)

where p is monthly contribution,

p= RS.1000

n= number of months,

r= rate of interest= 10%

and I= interest= Rs.5550

hence by substituting the values in eqn(1) we get

1000×[n(n+1)/24]×(10/100)= 5550 or

n (n+1)=(24/100)×5550= 1332

hence, n2+n-1332= (n+37) (n-36)=0

hence number of months=36

n=36

it means 3 years

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