Physics, asked by divyabharathi007, 1 year ago

preeti reached the metro station and found that the esclator was not working. she walked up the stationary esclator in time t1. on other days if she remains stationary on the moving esclator,then the esclator takes her up in time t2. the time taken by her to walk up on the moving esclator will be​

Answers

Answered by streetburner
4

Answer:

t1*t2 /(t1+t2)

Explanation:

Let d = distance covered

Speed of Preeti = p

Speed of escalator = e

t1 = d/p OR, p = d/t1

t2 = d/e OR, e = d/t2

Now, when she walks up on moving escalator then time T = d/e+p

= d

---------------------- = t1*t2/(t2+t1)

(d/t1) + (d/t2)

Answered by Rajeshkhandare
0

Aao na ab Mai to Aa gya

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