preparation of m/20 pxalic acid solution
bhalaraneha:
do u mean oxalic acid?
i think its oxalic acid
ok
nd its n/20 i think..not m/20
i think for here m/2 = n for this bcoz 2 hydroger
* hydrogen
i guess ur r8
Answers
Answered by
1
Molecular formula of oxalic acid: H2C2O4. 2H2O.
Molecular Wt. = 126. but here n/2 so = 63
to prepare 500 ml m/20 solution of acid 63 ×500 = 1.57 g of oxalic acid required.
(20×1000)
dissolved 1.57g acid in water and make it 500ml
Molecular Wt. = 126. but here n/2 so = 63
to prepare 500 ml m/20 solution of acid 63 ×500 = 1.57 g of oxalic acid required.
(20×1000)
dissolved 1.57g acid in water and make it 500ml
Answered by
2
Molecular formula of solid crystalline oxalic acid: H2C2O4, 2H2O.
Its Molecular Wt. 126.
Hence, to prepare 250 ml M/20 oxalic acid solution 126*250/(20*1000) = 1.575 gram of oxalic acid is to be dissolved in water in a 250 ml volumetric flask.
Its Molecular Wt. 126.
Hence, to prepare 250 ml M/20 oxalic acid solution 126*250/(20*1000) = 1.575 gram of oxalic acid is to be dissolved in water in a 250 ml volumetric flask.
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