Question

Prepare 0.1 Normal solution of H₂SO4 (Purity-98 %. Density= 1.83g/mL)​

Answer 1

Answer:

Molarity={(w/w%)×10×(density in g/ml)}÷(Molar mass of solute in g)

M = (98*10*1.8)/98

= 18M

Normality = Molarity * nfactor(For H2SO4 2,Dibasic acid)

= 18*2

= 36N

Molality =(1000*Molarity)/{(1000*density in g/ml)-(Molar mass of solute in g*Molarity)}

=(1000*18)/(1000*1.8)-(98*18)

= 18000/36=500m

Explanation:

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