Question

prepare 250 of a ml of a 2% sodium bicarbonate solution. the amount of sodium bicarbonate used will be?

Answer 1

Explanation:

We know that,

Molarity =

M×V

w

where, w = mass of Na

2

CO

3

in g,

M = molecular mass of Na

2

CO

3

in gram = 106

V = volume of solution in litre =

1000

250

=0.25

Molarity =

10

1

Hence,

10

1

=

106×0.25

w

or

w=

10

106×0.25

=2.65g

Answer 2

Answer:

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