Question

Principal = ₹3000, Rate= 10paise per rupee per annum, Time= 2year​

Answer 1

Correct Question:

Principal = ₹ 3000, Rate= 10 paise per rupee per annum, Time = 2year. Find S.I and Amount.

Answer:

S.I = ₹ 600

Amount = ₹ 3600

Step-by-step explanation:

Given that

Principal, p = ₹ 3000

Rate of intrest, r = 10/100 × 100 = 10% p.a

Time, t = 2 yrs.

To find the Simple Intrest and Amount.

We know that,

S.I = p×r×t/100

Substituting the values, we get,

=> S.I = 3000 × 10 × 2/100

=> S.I = 6000 /10

=> S.I = 600

Therefore, we have,

Simple Interest = ₹ 600

Now, we know that,

Amount = Principal + S.I

=> A = 3000+600

=> A = ₹ 3600

Hence, the required value of S.I and Amount is ₹ 600 and ₹ 3000 respectively.

Answer 2

Simple Interest ,

$\underbrace{\bf{S.I.=\dfrac{PTR}{100}}}$

where ,

• P denotes principal amount
• T denotes time in years
• R denotes rate of interest

Total Amount = Principal + S.I.

Given ,

Principal , P =  3,000

Rate of Interest , R =  ₹ 10 per annum

Time , T = 2 year

$\implies \bf{S.I.=\frac{3000*2*10}{100} }\\\\\implies \bf{S.I.= 600 }$

So , Total Amount = 3000 + 600

⇒ Total Amount = ₹ 3,600