Chemistry, asked by singhabhi1095, 10 months ago

Prepare m/50 solution of oxalic acid with the half of this determine the molarity and strength of kmno4

Answers

Answered by Anonymous
3

Answer:

KMnO4 is a self-indicator.

End Point

Colourless to permanent pink colour (KMnO4in burette).

Procedure

Weigh 1.260 g of oxalic acid crystals and dissove them in water to prepare 500 ml of M/50 oxalic acid solution using a 500 ml measuring flask. Rinse the pipette with the M/50 oxalic acid solution and pipette out 20 ml of it in a washed titration flask.

Rinse and fill the burette with M/100 KMnO4 solution.

Add one test-tube (~ 20 ml) full of dilute sulphuric acid (~ 2 M) to the solution in titration flask.

Note the initial reading of the burette.

Now add KMnO4 solution from the burette till a permanent light pink colour is imparted to the solution in the titration flask on addition of last single drop of KMnO4 solution.

Note the final reading of the burette.

Repeat the above steps 4-5 times to get a set of three concordant readings.

Observations

Weight of watch glass =……. g

Weight of watch glass + Mohr’s salt =…………..g

Weight of Mohr’s salt = 1.260 g

Volume of Mohr’s salt solution prepared = 500 ml

Volume of Mohr’s salt solution taken for each titration = 20.0 ml

Molarity of KMnO4 solution =M/50

Calculations

(a) Molarity of the KMnO4 solution

From the overall balanced chemical equation it is clear that 2 moles of KMnO4 react with 5 moles of oxalic acid.

#AnswerWithQuality

BAL

Similar questions