Question

Prese
USOS
The perimeter of a rectangle is 40 cm. The
length of the rectangle is more than double its
breadth by 2. Find length and breadth.
[3 Marks)​

Answer 1

Solution :

$\bf{\red{\underline{\bf{Given\::}}}}$

The perimeter of a rectangle is 40 cm. The length of the rectangle is more than double it's breadth by 2.

$\bf{\red{\underline{\bf{To\:find\::}}}}$

The length and breadth of the rectangle.

$\bf{\red{\underline{\bf{Explanation\::}}}}$

Let the breadth of rectangle be r

Let the length of rectangle be 2r + 2

We know that formula of the perimeter of rectangle:

$\boxed{\bf{Perimeter\:of\:rectangle=2(length+breadth)}}}}}$

A/q

$\longrightarrow\sf{2(l+b)=40}\\\\\longrightarrow\sf{2(2r+2+r)=40}\\\\\longrightarrow\sf{2(3r+2)=40}\\\\\longrightarrow\sf{6r+4=40}\\\\\longrightarrow\sf{6r=40-4}\\\\\longrightarrow\sf{6r=36}\\\\\longrightarrow\sf{r=\cancel{\dfrac{36}{6} }}\\\\\longrightarrow\sf{\pink{r=6\:cm}}$

Thus;

$\underbrace{\sf{The\:length\:of\:rectangle\:(2r+2)=[2(6)+2]=12+2=\boxed{\bf{14\:cm}}}}}\\\underbrace{\sf{The\:breadth\:of\:rectangle\:(r)=\boxed{\bf{6\:cm}}}}$