Math, asked by pankajtandon4954, 1 year ago

present age of a b c are in proporion of 10:11:12 5 yrs ago sum of their ages was 150 years then find current age

Answers

Answered by Anonymous
0
let the present age of a, b, c be 10x, 11x, 12x.
5 years ago,
age of a = 10x-5
age of b = 11x-5
age of c = 12x-5
According to question...
(10x-5) + (11x-5) + (12x-5) = 150
10x - 5 + 11x - 5 + 12x - 5 = 150
10x + 11x + 12x - 5 - 5 - 5 = 150
33x - 15 = 150
33x = 150 + 15
33x = 165
x = 165/33
x = 5

So,
the current age of a = 10 x 5 = 50
the current age of b = 11 x 5 = 55
the current age of c = 12 x 5 = 60
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