Question

present age of bitu is 2 more than 2 times of sidhi age.4 years before bitu age was 8 times of sidhi age.find the present age of bitu and sidhi.
WITH EXPLAINATION

Answer 1

⇝ Given :-

• Present age of Bitu is 2 more than 2 times of Sidhi's age.

• 4 years ago Bitu's age was 8 times of Sidhi's age.

⇝ To Find :-

• Their Present Ages

⇝ Solution :-

Let,

• Sidhi's Present Age = $\rm x$ years

As Present age of Bitu is 2 more than 2 times of Sidhi's age.

Therefore,

• Bitu's Present Age = = $\rm (2x+2)$ years

❒ Four Years Ago ;

• Sidhi's Age = $\rm (x-4)$ years

• Bitu's Age = $\rm (2x-2)$ years

⏩ According To Question :

$\blue \bigstar \: \red{\text{Bitu's Age = 8(Sidhi's Age)}}$

$:\longmapsto \rm 2x - 2 = 8(x - 4)$

$:\longmapsto \rm 2x - 2 = 8x - 32$

$:\longmapsto \rm 2x - 8x = - 32 + 2$

$:\longmapsto \rm \cancel- 6x = \cancel- 30$

$:\longmapsto \rm x = \cancel \frac{30}{6}$

$\purple{ \large :\longmapsto  \underline {\boxed{{\bf x = 5} }}}$

Hence,

Sidhi's Present Age = $\rm x$ = 5 years

Bitu's Present Age = = $\rm (2x+2)$ = 12 years

Therefore,

$\pink{\begin{cases} \bf Sidhi's\:Present\:Age = 5 \:years \\  \\  \bf Bitu's\:Present\:Age = 12 \: years\end{cases}}$

Answer 2

⚘ Question :-

• Present age of bitu is 2 more than 2 times of sidhi age. 4 years before bitu age was 8 times of sidhi age. Find the present ages of bitu and sidhi.

⚘ Answer :-

• Sidhi's present age = 5 years

• Bitu's present age = 12 years

Explanation:

⚘ Given :-

• Present age of bitu is 2 more than 2 times of sidhi age.

• 4 years before bitu age was 8 times of sidhi age.

⚘ To Find :-

• Their present ages?

⚘ Solution :-

• Let present age of sidhi be m years.

• As it is stated in question that present age of bitu is 2 more than 2 times of sidhi's age. So, present age of present age if bitu is (2m + 2) years.

★ Before 4 years their ages will be ::

• Age of sidhi = (m - 4) years

• Age of bitu = (2m + 2 - 4) years = (2m - 2) years

According to the Question,

• 4 years before bitu age was 8 times of sidhi age.

Therefore,

➨ $\sf 8(m - 4) = 2m - 2$

➨ $\sf 8m - 32 = 2m - 2$

➨ $\sf 8m - 2m = - 2 + 32$

➨ $\sf 6m = 30$

➨ $\sf m = {\cancel{\dfrac{30}{6}}}$

➨ $\bf\red{m = 5}$

∴ Present age of sidhi is 5 years.

Now,

➠ Present age of bitu = 2m + 2

Put m = 5 in above equation we get,

➠ Present age of bitu = (2 × 5) + 2

➠ Present age of bitu = 10 + 2

➠ Present age of bitu = 12 years

∴ Present age of bitu is 12 years.

⚘ Let's Verify :-

We know that,

• 4 years before bitu age was 8 times of sidhi age.

Therefore,

➨ $\sf 8(m - 4) = 2m - 2$

Put m = 5 in above equation we get,

➨ $\sf 8(5 - 4) = (2\:\times\:5) - 2$

➨ $\sf 8(1) = 10 - 2$

➨ $\sf 8\:\times\:1 = 8$

➨ $\sf 8 = 8$

➨ $\bf\purple{LHS = RHS}$

Hence, Verified ✔

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