Present age of man is equal to the age of his three daughters. After 20 years, if the age of his wife is subtracted from the then age of his three daughters, it becomes equal to the age of the man. Find the then age of his wife.
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let the present age of man be x.
,, age of wife be y
,, age of daughter be a, b, c.
ac to Question,
x=a+b+c... 1
after 20 years,
x+20=a+20+b+20+c+20-(y+20)
x+20=a+b+c+60-20-y
x+y=a+b+c+40-20
x+y=a+b+c+20... 2
subtracting 1 from 2 nd,
y=20
hence wife's age is 30years
,, age of wife be y
,, age of daughter be a, b, c.
ac to Question,
x=a+b+c... 1
after 20 years,
x+20=a+20+b+20+c+20-(y+20)
x+20=a+b+c+60-20-y
x+y=a+b+c+40-20
x+y=a+b+c+20... 2
subtracting 1 from 2 nd,
y=20
hence wife's age is 30years
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