Question

Present age of mother is four times the sum of the ages of her two daughters. After 5 years mother age will be twice the sum of the ages of the two daughters.what is the present age of mothe?

Answer 1

$\bf{\huge {\underline {\boxed {\sf\purple {Answer:\:150 \:years}}}}}$

$\huge\sf\pink {Given:}$

Age of mother = 4 ( age of child 1 + age of child 2 )

$\huge\sf\pink {Assume :}$

Let present age of mother be ' M ' years.

1st child be ( a ) years

2nd Child be ( b ) years

$\huge\sf\blue {To \:Find :}$

• Present age of mother

$\huge\sf\pink {Solution :}$

According to Question,

Present age of mother ( M ) = 4 ( a + b ) ------ ( i )

Now,

After 5 years,

M + 5 = 2 ( a + b + 10 ) -----( add 5 in both the sides )

( Multiply by 2 in both the sides )

➡ 2 ( M + 5 ) = 2×2 ( a + b + 10 )

➡ 2M + 10 = 4 ( a + b + 10 )

➡ 2M + 10 = 4 ( a + b ) + 40

➡ 2M = M + 160 - 10 ---- ( By using ( i ) )

➡ 2M - M = 150

➡ M = 150 years

Answer: Present age of mother is 150 years.

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$\huge\mathscr\red {Be\: Brainly!!!}$