Math, asked by laxmisrivastavpe9kbh, 1 year ago

present age of sangini's mother is four times sangini's age . five years hence age will be 21 years more than sangini age . find their present age

Answers

Answered by dhatraditya
8

let sangini's age be S

let her mother's age be M

Problem states that mother is 4 times sangini's age

so, M = 4 x S

in 5 years, both the mom and sangini will be 5 years older, so their ages will be S+5 and M+5

Provlem says that mom will be 21 years more than Sangini 5 years from now,

so M+5 = S+5+21

So you have two statements

M = 4S

M+5 = S+5+21

solve for M and S


Answered by prakrutimaitreer
1

Answer:

26 mother age and 6 baby age

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