Question

pressure of 1 gram of an ideal gas ke 27 degree celsius is found to be 2 bar when to gram another ideal gas is introduced in the same flask at same temperature the pressure becomes three were find the relationship between their molecular masses​

Answer 1

Answer:

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Explanation:

Let M and M' be the molar masses of ideal gases A and B respectively.

The number of moles of gas A and B are  M1 and M′2 respectively.

Let P and P' be the pressures of gases A and B respectively.

P=2 bar

P+P′=3 bar

P′=3−2=1 bar

The ideal gas equations for two gases A and B are,

PV=nRT......(i)

P′V=n′RT......(ii)

Divide equation (i) by equation (ii). 

P′P=n′n=2×M1×M′=2MM′

MM′=2P′P=12×2=4

M′=4M