Pressure of 20L gas at constant Temperature is 2 atm. What will be New volume If Pressure is increased to 3 atm at the same temperature?
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Answer:-
Given:
Initial Pressure of a gas (P1) = 2 atm
Initial Volume (V1) = 20 L
Final Pressure (P2) = 3 atm.
Final Volume (V2) = ?
We know that,
Boyle's law of gases states that at constant temperature the pressure of a gas is inversely proportional to it's Volume.
→ P ∝ 1/V
→ PV = k (Constant)
→ P1V1 = P2V2
→ (2) * (20) = (3) * V2
→ 40/3 = V2
→ 13.33 L = V2
Hence, the volume of the gas decreases to 13.33 L.
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