Question

price of an article decreases by 10% last year and this year increases by 20%. Find percentage increased during 2 years

Answer 1

$\huge{\ulcorner {\red{Hey \:mate}}} \rfloor$

✨$<b>Here's ur answer$

➡️ Given,
Percentage decreased last year=10%

Percentage increased in the next two years =20%

So let us consider the original price as $100

So the loss incurred last year = $90
(10% of 100 -$100)

And the gain =20% of 90=$18

So incrment=$90+$18=$108

Now,

Percentage =8/100×100=
8%

Answer 2

Let the Price of article be "X"

Then Price decreased in 1st Year = 10%
New price =
$x \times \frac{90}{100} = \frac{9x}{10}$
Now , Price increased in 2nd year is 20%

New price -

$\frac{9x}{10} \times \frac{120}{100} = \frac{27x}{25}$
Price of article increased during 2 years =

$\frac{27x}{25} - x = \frac{2x}{25}$
Percentage increased =
$\frac{ \frac{2x}{25} }{x} \times 100 = 8\%$