Question

Prime factorisation of 1458

Answer 1

Answer

$hey \: mate\\ \\ 1458 \div 2 = 729 \\ 729 \div 3 = 243 \\ 243 \div 3 = 81 \\ 81 \div 3 = 27 \\ 27 \div 3 = 9 \\ 9 \div 3 =3 \\ 3 \div 3 = 1 \\ \\ so \: \\ prime \: fctors \: of \: 1458 \: are \\ 2 \times 3 \times 3 \times 3 \times 3 \times 3 \times 3$

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Answer 2

Answer:

1458 = 2 × 3^6

Step-by-step explanation:

Prime Factors of 1458 = 2 × 3 × 3 × 3 × 3 × 3 × 3

= 2 x 3^6