Question

Show that n square minus 1 is always divisible by 2

Answer 1

Answer:

Step-by-step explanation:

n^2 - 1 =[n-1] [n+1]

if n is odd    n+1  and n-1 are even    n^2 -1 is even

 then divisible by 2

if n is even  n+1  and n-1 are   odd    n^2 -1 is odd  

then it is not  divisible by 2

note

change your question   n^2 - n    = n [n-1]

   clearly n or n - 1 is even

   so n[n-1] is even

    n^2 - n is even

Answer 2

$\mathfrak{\huge{\red{ANSWER}}}$

$<font color = "blue"><marquee>To show n² - 1 </font color="blue"></marquee>$

Is DIVISIABLE BY 2

= n² - 1

= ( n + 1 ) ( n - 1)

Here only N is Odd &( N + 1 )& ( N +2)

are even

& as we know number which is divisiavle by 2 is called an Even Number

So it Divisiable by 2