Question

prime factorization of a natural number n is 2 cube* 3square*5square*7, write the number of consecutive zeroes in n

Answer 1

two zeroes will be there

Answer 2

n = 2^3 * 3^2 * 5^2 * 7 = 4*2*9*25*7 = 4*25*9*2*7 = 100 * 9*2*7
Now, we can see that since there is a multiplication involving '100', there will be 2 consecutive zeroes in 'n'
[n = 12600].
Hope it helps.