Question

principal=10800₹ rate=12.5% time=3 years find compound interest with formula A=P (1 + R/100) ^T​

Answer 1

$\large\underline{\sf{Solution-}}$

Given that,

Principal, P = Rs 10800

Rate of interest, r = 12.5 % per annum compounded annually

Time, n = 3 years

We know,

Amount on a certain sum of money of Rs P invested at the rate of r % per annum compounded annually for n years is given by

$\boxed{\tt{ \: \: Amount \: = \: P {\bigg[1 + \dfrac{r}{100} \bigg]}^{n} \: \: }}$

So, on substituting the values, we get

$\rm \: \: Amount \: = \: 10800 {\bigg[1 + \dfrac{12.5}{100} \bigg]}^{3}$

$\rm \: \: Amount \: = \: 10800 {\bigg[1 + \dfrac{125}{1000} \bigg]}^{3}$

$\rm \: \: Amount \: = \: 10800 {\bigg[1 + \dfrac{1}{8} \bigg]}^{3}$

$\rm \: \: Amount \: = \: 10800 {\bigg[\dfrac{8 + 1}{8} \bigg]}^{3}$

$\rm \: \: Amount \: = \: 10800 {\bigg[\dfrac{9}{8} \bigg]}^{3}$

$\rm \: \: Amount \: = \: 10800 \times \dfrac{9}{8} \times \dfrac{9}{8} \times \dfrac{9}{8}$

$\rm \: \: Amount \: = \: Rs \: 15377.34$

So,

$\rm \: Compound\:Interest = Amount - Principal$

$\rm \: Compound\:Interest = 15377.34 - 10800$

$\rm\implies \:Compound\:Interest \: = \: Rs \: 4577.34$

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ADDITIONAL INFORMATION

1. Amount on a certain sum of money of Rs P invested at the rate of r % per annum compounded semi - annually for n years is given by

$\boxed{\tt{ \: \: Amount \: = \: P {\bigg[1 + \dfrac{r}{200} \bigg]}^{2n} \: \: }}$

2. Amount on a certain sum of money of Rs P invested at the rate of r % per annum compounded quarterly for n years is given by

$\boxed{\tt{ \: \: Amount \: = \: P {\bigg[1 + \dfrac{r}{400} \bigg]}^{4n} \: \: }}$

3. Amount on a certain sum of money of Rs P invested at the rate of r % per annum compounded monthly for n years is given by

$\boxed{\tt{ \: \: Amount \: = \: P {\bigg[1 + \dfrac{r}{1200} \bigg]}^{12n} \: \: }}$

Answer 2

Refer the Given Attachment.