Question

Principal = ₹5000, amount = ₹6450 and rate 12% p.a.
Then Find The Time​

Answer 1

Given :-

• Principal (P) = ₹5000
• Amount (A) = ₹6450
• Simple Interest (SI) = A - P = ₹(6450 - 5000) = ₹1450
• Rate (R) = 12% per annum

To Find :-

• Time (T)

Solution :-

We know that,

$\sf \fbox {Time = \dfrac{100 \times SI}{P \times R}}$

$\sf T = \frac{100 \times 1450}{5000 \times 12}$

Canceling the zeros,

$\sf T = \frac{1\cancel{00} \times 145\cancel{0}}{5 \cancel{00} \cancel{0} \times 12}$

$\sf T = \frac{ \cancel{145}}{ \cancel{5} \times 12}$

$\sf T = \frac{29}{12}$

$\sf T = 2.5$

Hence the time period is 2.5 years or 2 years and 5 months.