principal is rupees 8000 and rate is 10 percent and time is 2 years find compounded annually
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Answer:
Answer
Answer⇒ Compound interest (C.I)=P[(1+
Answer⇒ Compound interest (C.I)=P[(1+ 100
Answer⇒ Compound interest (C.I)=P[(1+ 100r
Answer⇒ Compound interest (C.I)=P[(1+ 100r
Answer⇒ Compound interest (C.I)=P[(1+ 100r )
Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t
Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]
Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time
Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+
Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 100
Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005
Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005
Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005 )
Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005 ) 2
Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005 ) 2 −1]
Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005 ) 2 −1]=8000[
Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005 ) 2 −1]=8000[ 1000
Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005 ) 2 −1]=8000[ 100025
Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005 ) 2 −1]=8000[ 100025
Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005 ) 2 −1]=8000[ 100025 +
Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005 ) 2 −1]=8000[ 100025 + 100
Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005 ) 2 −1]=8000[ 100025 + 10010
Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005 ) 2 −1]=8000[ 100025 + 10010
Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005 ) 2 −1]=8000[ 100025 + 10010 ]=8000[
Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005 ) 2 −1]=8000[ 100025 + 10010 ]=8000[ 10000
Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005 ) 2 −1]=8000[ 100025 + 10010 ]=8000[ 1000025+1000
Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005 ) 2 −1]=8000[ 100025 + 10010 ]=8000[ 1000025+1000
Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005 ) 2 −1]=8000[ 100025 + 10010 ]=8000[ 1000025+1000 ]
Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005 ) 2 −1]=8000[ 100025 + 10010 ]=8000[ 1000025+1000 ]⇒C.I=
Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005 ) 2 −1]=8000[ 100025 + 10010 ]=8000[ 1000025+1000 ]⇒C.I= 10
Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005 ) 2 −1]=8000[ 100025 + 10010 ]=8000[ 1000025+1000 ]⇒C.I= 108
Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005 ) 2 −1]=8000[ 100025 + 10010 ]=8000[ 1000025+1000 ]⇒C.I= 108
Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005 ) 2 −1]=8000[ 100025 + 10010 ]=8000[ 1000025+1000 ]⇒C.I= 108 [1025]=14.820.
Compound interest = Rs 1680.
Step-by-step explanation:
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