Question

principal is rupees 8000 and rate is 10 percent and time is 2 years find compounded annually​

Answer 1

Answer:

Answer

Answer⇒ Compound interest (C.I)=P[(1+

Answer⇒ Compound interest (C.I)=P[(1+ 100

Answer⇒ Compound interest (C.I)=P[(1+ 100r

Answer⇒ Compound interest (C.I)=P[(1+ 100r

Answer⇒ Compound interest (C.I)=P[(1+ 100r )

Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t

Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]

Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time

Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+

Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 100

Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005

Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005

Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005 )

Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005 ) 2

Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005 ) 2 −1]

Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005 ) 2 −1]=8000[

Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005 ) 2 −1]=8000[ 1000

Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005 ) 2 −1]=8000[ 100025

Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005 ) 2 −1]=8000[ 100025

Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005 ) 2 −1]=8000[ 100025 +

Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005 ) 2 −1]=8000[ 100025 + 100

Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005 ) 2 −1]=8000[ 100025 + 10010

Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005 ) 2 −1]=8000[ 100025 + 10010

Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005 ) 2 −1]=8000[ 100025 + 10010 ]=8000[

Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005 ) 2 −1]=8000[ 100025 + 10010 ]=8000[ 10000

Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005 ) 2 −1]=8000[ 100025 + 10010 ]=8000[ 1000025+1000

Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005 ) 2 −1]=8000[ 100025 + 10010 ]=8000[ 1000025+1000

Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005 ) 2 −1]=8000[ 100025 + 10010 ]=8000[ 1000025+1000 ]

Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005 ) 2 −1]=8000[ 100025 + 10010 ]=8000[ 1000025+1000 ]⇒C.I=

Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005 ) 2 −1]=8000[ 100025 + 10010 ]=8000[ 1000025+1000 ]⇒C.I= 10

Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005 ) 2 −1]=8000[ 100025 + 10010 ]=8000[ 1000025+1000 ]⇒C.I= 108

Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005 ) 2 −1]=8000[ 100025 + 10010 ]=8000[ 1000025+1000 ]⇒C.I= 108

Answer⇒ Compound interest (C.I)=P[(1+ 100r ) t −1]P= Principal r= rate, t= time⇒ C.I. =8000[(1+ 1005 ) 2 −1]=8000[ 100025 + 10010 ]=8000[ 1000025+1000 ]⇒C.I= 108 [1025]=14.820.

Answer 2

Compound interest = Rs 1680.

Step-by-step explanation:

$\green{Given, Principal=Rs 8000}$

$\blue{Rate=10 percent-per-annum}$

$\green{Time=2years}$

So, Amount

=$Rs[P(1+\frac {r}{100})]ⁿ$

=$Rs[8000(1+\frac {10}{100})]²$

=$\frac {8000*110*110}{100*100}$

=$Rs (121*80)$

=$Rs9680$

So, $\blue{C.I.}=Rs (9680-8000)=Rs 1680.$

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