Math, asked by gunavadhini, 3 months ago

Principal (P) =
5.000 ; Time (T) = 3 years; Amount (A)=6500.
Find the interest rate (R) and Simple Interest (SI).​

Answers

Answered by Anonymous
24

Answer :-

Given :-

  • Principal = Rs. 5000
  • Amount = Rs. 6500
  • Time = 3 years

To Find :-

  • Simple interest
  • Rate of interest

Solution :-

We know that,

→ Simple interest = Amount - Principal

→ SI = 6500 - 5000

→ SI = 1500

Simple interest = Rs. 1500

Substituting the value of simple interest, time and principal in the formula of simple interest :-

→ SI = P × R × T / 100

→ 1500 = 5000 × 3 × R / 100

→ 1500 = 50 × 3 × R

→ 1500 = 150R

→ R = 1500 / 150

→ R = 10%

Rate of interest = 10%

Answered by 12thpáìn
9

Given

  • Principal (P)= 5000
  • Time (T)= 3 year's
  • Amount (A)= 6500

To Find

  • Simple Interest (SI)
  • Rate (R)

____________________

Formula Used

  •  \boxed{ { \mathfrak{si \:  = amount -  principal}}}
  •  \boxed{ \mathfrak{si =  \dfrac{principal \times \: time  \times rate}{100}}}

_____________________

Solution

Here,

  • Amount= 6500
  • Principal= 5000

 →\sf \: SI = Amount- Principal

 →\sf \: SI =6500 - 5000

 ~~~\sf \: SI =1500\\

Now

 \\\sf \: SI =  \dfrac{principal \times time \times rate}{100}

 →\sf \: 1500=  \dfrac{5000 \times 3 \times rate}{100}

→\sf \:rate =  \dfrac{150000}{15000}

~~~\sf \:rate = 10\%

  • Simple Interest= Rs.1500
  • Rate=10%
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