Math, asked by Himanshu978, 1 year ago

principal value of this angle

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Answered by tnwramit1
0
Given

 \sec^{ - 1} - ( \sqrt{2})
There is no option for theta so I m using A for theta

a = \sec ^{ - 1} ( - \sqrt{2} )

 \sec \: a = - \sqrt{2}

Sec a = 1/cos a

So

1/cos a = - root 2

Cos a=1/- root 2

And cos 135=1/-root 2

So theta (a) =135

This is ur ans hope it will help you in case of any doubt comment below
Answered by DharamveerSingh
0
hope it will be helpful for you
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