principle 10000 rate of interest 10% time 2 year find compound interest
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Answered by
1
Given P = 10000, R = 10%, T = 2 years.
We know that A = P(1 + r/100)^n
= 10000(1 + 10/100)^2
= 10000(1 + 1/10)^2
= 10000(11/10)^2
= 10000 * 121/100 * 121/100
= 12100.
We know that Compound Interest = A - P
= 12100 - 10000
= 2100.
Therefore the compound interest = 2100.
Hope this helps!
We know that A = P(1 + r/100)^n
= 10000(1 + 10/100)^2
= 10000(1 + 1/10)^2
= 10000(11/10)^2
= 10000 * 121/100 * 121/100
= 12100.
We know that Compound Interest = A - P
= 12100 - 10000
= 2100.
Therefore the compound interest = 2100.
Hope this helps!
sonali35:
how 12100 come plz reply
Let me explain you in a more simple way
10000(1 + 10/100)^2
= 10000(100 + 10/100)^2
= 10000(110/100)^2
= 10000(1.1)^2
= 10000 * 1.21
= 12100
= 10000(100 + 10/100)^2
= 10000(110/100)^2
= 10000(1.1)^2
= 10000 * 1.21
= 12100
dnt understnd yaa
Okk Sonali..Tell me in which step u r having doubt?
Answered by
0
2100 is the right ans..
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