Question

principle=640,rate=12 1/2 time=6 months, find the SI along with amount​

Answer 1

Answer:

$principal = 640 \\ rate \: of \: interest = 12 \frac{1}{2} \% \\ = \frac{25}{2} \% \\ time = 6 \: month \\ = \frac{6}{12} yrs \\ \\ simple \: interest = \frac{ p\times \: r \times t}{100} \\ = \frac{640 \times 25 \times 6}{(2 \times 100 )\times 12} \\ = 40 \\ {\boxed{s.i =rs .\: 40 }} \\ amount = principal + simple \: interest </p><p>\\= 640 + 40 \\ = 680$

I HOPE IT WILL HELP YOU DEAR....

Answer 2

Answer:-

$\red{\bigstar}$ Simple Interest $\large\leadsto\boxed{\tt\green{Rs. \: 40}}$

$\red{\bigstar}$ Amount $\large\leadsto\boxed{\tt\green{Rs. \: 680}}$

• Given:-

• Principal = Rs. 640

• Rate = 12 ½% → 25/2 % p.a

• Time = 6 months → 1/2 years

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

• To Find:-

• Simple Interest [ S.I ]

• Amount [ A ]

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

• Solution:-

❶

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

We know,

$\purple{\bigstar}$ $\large\underline{\boxed{\bf\red{S.I = \dfrac{P \times R \times T}{100}}}}$

where,

• S.I = Simple Interest

• P = Principal

• R = Rate

• T = Time

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

• Substituting in the Formula:-

➪ $\sf S.I = \dfrac{640 \times 25 \times 1}{100 \times 2 \times 2}$

➪ $\sf S.I = \dfrac{16000}{400}$

★ $\bf\pink{S.I = Rs. 40}$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

❷

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

We know,

$\purple{\bigstar}$ $\large\underline{\boxed{\bf\red{Amount = P + S.I}}}$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

• Substituting in the Formula:-

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

➪ $\sf Amount = 640 + 40$

★ $\bf\pink{Amount = Rs. 680}$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

Therefore, the S.I and Amount are Rs. 40 and Rs. 680 respectively.