Question

principle solution of sec=2/root3​

Answer 1

Step-by-step explanation:

secx = 2 /√3

☑ principal solution =

The solution of trigonometric equation of an unknown angle angle 'x ' , where 0 < x < 2π , are called it's principal solution

☑ so we have, secx = 2/ √3 , we have to find its principal solution ,means the values of angle x belongs to

0 < x < 2π

secx = 2 /√3,

secx = sec ( π / 6 ) ,

sec x = sec(2π - π/ 6 ) = sec(11π /6)

therefor ,

0 < π/6 < 2π and 0< 11π /6< 2π

therefore, the principal solutions are

x = π / 6 and x = 11π/6