principle solution of
sinx=1/√2
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Answered by
1
Answer:
We know that
sinx=
2
1
=sin
4
π
and by allied angles, we also know that
sin(π−x)=sinx
∴sin
4
π
=sin(π−
4
π
)=sin
4
3π
∴sin
4
π
=sin3π4=
2
1
such that 0<
4
π
<2π and 0<
4
3π
<2π
∴ the required principal solution are x=
4
π
and x=
4
3π
Step-by-step explanation:
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