Pritha draws a parallelogram of which adjacent sides are 25cm and 15cm and length of
one diagonal is 20cm. Let us write by calculating the height of parallelogram which is
drawn on the side of 25 cm.
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Given, a parallelogram of which adjacent sides are 25 cm and 15 cm and length of one diagonal is 20 cm.
Consider a parallelogram ABCD, adjacent sides are given, AB=25cm
BC=15cm
And diagonal AC=20cm
Semi perimeter of ∆ABC, S =
S = 30cm
Hence area of ∆ABC =
sq. cm
Area ∆ABC = 150 sq. cm
Area of parallelogram ABCD = 2×area of ∆ABC
Area of parallelogram ABCD = 2×150
= 300sq. cm
Let, Height AE = h
Area of parallelogram ABCD= base × height
⟹ 300 = 25 × h
⟹ h =
⟹ h = 12cm
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