Verify |x+y|< |×|+|y| for x=-1/5, y=3/25
Answers
Answered by
1
Step-by-step explanation:
|x + y | = | -1/5 + 3/25|
= |( -5+3)/25|
= |-2/25|
= 2/25
|x| + |y| = |-1/5| + |3/25|
= 1/5 + 3/25
= 5+3/25
= 8/25
3/25 < 8/25
so,
|x + y | < |x| + |y|
Answered by
0
Answer:
x=1/5, y=3/25
LHS
|1/5+3/25|
=| 5+3/25|
=|8/25|
=8/25
RHS
|1/5|+|3/25|
=1/5+3/25
= 5+3/25
=8/25
SO LHS = RHS
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