Priya can do a work in 16 days. In how many days will the work be completed by Sai, if the efficiency of Sai is 60% more than that of Priya ?
A) 8 days
B) 12 days
C) 14 days
D) 10 days
Answers
Answered by
0
We will solve this using the LCM technique.
A takes 10 days & B takes 15 days. So, let the total work be LCM(10,15) = 30 Units
A -> 10 days = 3 Units/dayB -> 15 days = 2 Units/day
A + B = 5 Units/day
Thus, TOTAL TIME = 155155 = 3 Days (Answer)
A takes 10 days & B takes 15 days. So, let the total work be LCM(10,15) = 30 Units
A -> 10 days = 3 Units/dayB -> 15 days = 2 Units/day
A + B = 5 Units/day
Thus, TOTAL TIME = 155155 = 3 Days (Answer)
Answered by
4
Heyy mate ❤✌✌❤
Here's your Answer...
⤵️⤵️⤵️⤵️⤵️⤵️
Ratio of efficiencies of Priya and Sai is
Sai : Priya = 160 : 100 = 8 : 5
Given Priya completes the work in 16 days
Let number of days Sai completes the work be 'd'
=> 5×16 = 8×d
d = 10 days.
Therefore, number of days Sai completes the work is 10 days.
✔✔✔
Here's your Answer...
⤵️⤵️⤵️⤵️⤵️⤵️
Ratio of efficiencies of Priya and Sai is
Sai : Priya = 160 : 100 = 8 : 5
Given Priya completes the work in 16 days
Let number of days Sai completes the work be 'd'
=> 5×16 = 8×d
d = 10 days.
Therefore, number of days Sai completes the work is 10 days.
✔✔✔
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