Pro 6 + root 2 is irrational
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Let us assume that 6+√2 is a rational number and can be written in the form of P/Q where P and Q is an irrational number and q is not equal to zero.
6+√2= P/Q
√2 = p/q -6
√2 = 6p-6/6q
So, 6p-6/6q is a rational number
But in LHS √2 is irrational no which is not possible.
Therefore our assumption is wrong 6+√2 is an irrational number.
Hence proved
Hope it helps you.
mark it brainlist please.
Let us assume that 6+√2 is a rational number and can be written in the form of P/Q where P and Q is an irrational number and q is not equal to zero.
6+√2= P/Q
√2 = p/q -6
√2 = 6p-6/6q
So, 6p-6/6q is a rational number
But in LHS √2 is irrational no which is not possible.
Therefore our assumption is wrong 6+√2 is an irrational number.
Hence proved
Hope it helps you.
mark it brainlist please.
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