Question

Prob (8) Two point charges 12 nC and -16 nC are placed respectively at the corners
A and C of a A ABC of sides AB 0.04 m, BC = 0.03 m and CA = 0.05 m. Find the
resultant field at the corner B.​

Answer 1

Answer:

The net electric field is given as,

E=2×

⎣

⎢

⎢

⎢

⎢

⎢

⎡

4πε

0

1

×

((d

1

)

2

+(d

2

)

2

)

2

3

Q

1

d

1

⎦

⎥

⎥

⎥

⎥

⎥

⎤

=2×

⎣

⎢

⎢

⎢

⎢

⎢

⎡

9×10

9

×

((5×10

−2

)

2

+(12×10

−12

)

2

)

2

3

10×10

−6

×(5×10

−2

)

⎦

⎥

⎥

⎥

⎥

⎥

⎤

=4.096×10

6

V/m

Thus, the electric field is 4.096×10

6

V/

Answer 2

Answer:

जिगर वालों को डर से कोई वास्ता नहीं होता,

हम वहाँ भी कदम रखते हैं जहाँ कोई रास्ता नहीं होता..