Prob (8) Two point charges 12 nC and -16 nC are placed respectively at the corners
A and C of a A ABC of sides AB 0.04 m, BC = 0.03 m and CA = 0.05 m. Find the
resultant field at the corner B.
Answers
Answered by
0
Answer:
The net electric field is given as,
E=2×
⎣
⎢
⎢
⎢
⎢
⎢
⎡
4πε
0
1
×
((d
1
)
2
+(d
2
)
2
)
2
3
Q
1
d
1
⎦
⎥
⎥
⎥
⎥
⎥
⎤
=2×
⎣
⎢
⎢
⎢
⎢
⎢
⎡
9×10
9
×
((5×10
−2
)
2
+(12×10
−12
)
2
)
2
3
10×10
−6
×(5×10
−2
)
⎦
⎥
⎥
⎥
⎥
⎥
⎤
=4.096×10
6
V/m
Thus, the electric field is 4.096×10
6
V/
Answered by
0
Answer:
जिगर वालों को डर से कोई वास्ता नहीं होता,
हम वहाँ भी कदम रखते हैं जहाँ कोई रास्ता नहीं होता..
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