Question

Probability of 53 sundays and 53 tue in a leap year

Answer 1

Answer:

the probability for both of them is

$\frac{2}{7}$

Answer 2

Answer:

We know that there are 366 days in a leap year = 52 weeks + 2 days.

These 2 days can be:

1. {Sun, mon}

2. {Mon, Tues}

3. {Tues, Wed}

4. {Wed, Thurs}

5. {Thurs, Fri}

6. {Fri, Sat}

7. {Sat, Sun}

n(s) = 7.

Now,

Out of these 7 outcomes, the favorable outcomes are 2.(mon, tues),(tues, wed).

n(a) = 2.

Therefore the required probability p(A) = n(A)/n(S)

                                                                 = 2/7.