Question

probability of choosing box 1 and getting gold coin is a) 1/6 b) 2/3 c) 1/3 d) 1/2​

Answer 1

Answer:

Step-by-step explanation:

given that, B1={G,G}

B2={S,S}

B3={G,S}

P(B1)=P(B2)=P(B3)=13

P(G∣B1)=1

P(G∣B2)=0

P(G∣B3)=12

By baes theorem

P(B1∣G)=P(B1).P(B2)/P(BI)P(G∣B1)+P(B2)P(G∣B2)+BP(B3)P(G∣B3)

=1/3/1/3+3⋅0+1/3⋅1/2

=1/1+1/2

=1/3/2

=2/3

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