Question

Probability of getting 3 conseecutive head on 5 toss

Answer 1

Answer:

Assuming each coin toss is fair and independent of each other:

Pr(3 consecutive head)= $\frac{3\cdot \left(2\cdot 2\right)}{2^5}=\frac{12}{32}=\frac{3}{8}$

Hope this is correct and hope it helps :)

Step-by-step explanation:

There are three ways of positioning '3 consecutive', either starting at round 1, 2 or 3. 2×2 represents total outcome of the remaining two rounds, which is multiplied with 3 to get total ways of obtaining 3 consecutive heads. Total outcome is 2^5=32.