probability of getting a consonant from english alphabates is
Answers
Answered by
4
let no of consonants be n (C)
sample space S = {A,B,C,D,.........Z}
n (S)= 26
C= {b,c,d,.......z}
n (C)= 21
P(C)=n (C)/n (s)
= 21/26
sample space S = {A,B,C,D,.........Z}
n (S)= 26
C= {b,c,d,.......z}
n (C)= 21
P(C)=n (C)/n (s)
= 21/26
Answered by
3
No. of Consonants = 21 (26-5)
Total outcome of all letters = 26
P(E) = 21/26
Total outcome of all letters = 26
P(E) = 21/26
Similar questions