Math, asked by kalpit314, 1 year ago

Probability of throwing more than 4 in a single throw from an ordinary die

Answers

Answered by smithasijotsl
0

Answer:

Probability of throwing more than 4 in a single throw from an ordinary die = \frac{1}{3}

Step-by-step explanation:

Given a die is thrown

To find,

The probability of throwing more than 4.

Recall the formula

Probability = \frac{no\ of \ possible \ outcomes }{ Total \ number \ of \ outcomes}

When a die is thrown, the Total number of outcomes = 6

No. of possible outcomes of throwing more than 4 = 2

Hence probability = \frac{no\ of \ possible \ outcomes }{ Total \ number \ of \ outcomes} = \frac{2}{6} = \frac{1}{3}

Probability of throwing more than 4 in a single throw from an ordinary die = \frac{1}{3}

#SPJ3

Similar questions