Question

Probability of winning game is 1 upon 3 more than twice of probability of losing match. Find probability of winning and losing the match

Answer 1

max probability of a task is 100 ...so x be the probability of winning the game n y be the probability for losing the game
i) 2y + 1/3 = x ; 6y + 1 = 3x
ii) x + y = 100 ; x = 100 - y 
Now putting the value of x in (ii) in (i), we have,
6y + 1 = 3(100-y)
= 6y + 1 = 300 - 3y
= 9y = 299
= y =299/9 = 33.22% (losing)
Therefore, probability of winning = 100 -  33.22 = 66.78%