Question

Probability Q.26 Class 10​

Answer 1

S = {1,2,3,4,5,6}

n(S)= 6

Event A: a number between 2 and 6

A= {3,4,5}

n(A)= 3

P(A)= 2

Event B: An odd number

B= {1,3,5}

n(B)= 3

P(B)= 2

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Answer 2

Heya!!

Total cases- 1 , 2 , 3 , 4 , 5, 6

Total no. of outcomes = 6

i) Favourable cases = 3 , 4, 5

favourable outcomes = 3

Probability of a no. lying between 2 & 6

= 3/6

= 1/2

ii) Favourable cases =1, 3,5

favourable outcomes = 3

probability of getting an odd number

= 3/6

= 1/2

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