Question

probability sums plz solve these:-

Answer 1

getting a sum more than 10
probability=3/36=1/12
the no. are (5,6) and (6,5) also (6,6) are the sum which are greater than 10.

sum of multiple of 6 and 3
6 multiple=6,12,18,24,30,36,42
3 multiple=3,6,9,12,15,18,21,24,27,30,33,36
common no.=6,12,18,24,24,30,36
now find the sum...
but we found that sum are coming only of 2 no. so find that
probability=6/36=6

Answer 2

Solution :

{ The event points of rolling two dice simultaneously are mentioned in the attachment added. }

Thus, total number of event points

= 6 × 6 = 36

(a)

Now, the event points favourable to the event "sum more than 10"

= {(5, 6), (6, 5), (6, 6)}

Thus, the number of event points to the event "sum more than 10"

= 3

Therefore, the required probability of getting "sum more than 10"

= 3/36 = 1/12 (Ans.)

(b)

Now, the event points favourable to the event "sum more than 6 and a multiple of 3"

= {(3, 6), (4, 5), (5, 4), (6, 3), (6, 6)}

Thus, the number of event points to the event "sum more than 6 and a multiple of 3"

= 5

Therefore, the required probability of getting "sum more than 6 and a multiple of 3"

= 5/36 (Ans.)