Question

Probability (up to one decimal place) of consecutively picking 3 red balls without replacement from a box containing 5 red balls and 1 white ball is

Answer 1

Answer: 0.5

Step-by-step explanation:

Since, total red balls = 5

total white balls = 1

⇒The total balls = 5 + 1 = 6,

Therefore, the probability of getting 3 red balls = $\frac{5_C_3}{6_C_3} = \frac{\frac{5!}{3!2!}}{\frac{6!}{3!3!}} = \frac{5!\times 3!}{6!\times 2!} =\frac{120\times 6}{720\times 2} = \frac{1}{2} = 0.5$

Thus, the required probability = 0.5