Question

PROBLEM 11. A bus starting from rest moves with a
uniform acceleration of 0.1 m s? for 2 minutes. Find
(a) the speed acquired (b) the distance travelled.
(NCERT)​

Answer 1

Explanation:

 A bus starting from rest moves with a uniform acceleration of 0.1 m s-2 for 2 minutes. Find (a)the speed acquired, (b) the distance travelled. Thus, the bus will acquire a speed of 120 m/s after 2 minute with the given acceleration. Thus, bus will travel a distance of 720 m in the given time of 2 minute

Answer 2

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The bus starting from rest moves with a uniform acceleration of 0.1 ms^-2 for 2 minutes .

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Acceleration and distance travelled

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(a) Acceleration

The bus starts from rest.

Therefore, initial velocity (u) = 0 m/s

Acceleration (a) = 0.1 m.s^-2

Time = 2 minutes = 120 s

Acceleration is given by the equation

$a = \frac{(v - u)}{t}$

Therefore, terminal velocity (v) = (at) + u

$(0.1 \: m {s}^{ - 2} \times 120s) + 0 m {s}^{ - 1}$

$12 \: m {s}^{ - 1} + 0 \: m {s}^{ - 1}$

Therefore, terminal velocity (v) = 12 m/s

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(b) As per the third motion equation,

Since a = 0.1 ms^-2, v = 12 ms^-1, u = 0 ms^-1, and t = 120s, the following value for s (distance) can be obtained.

$Distance, s = \frac{( {v}^{2} - {u}^{2})}{2a}$

$\frac{( {12}^{2} - {0}^{2} )}{2(0.1)}$

$Therefore, s = 720m.$

The speed acquired is 12ms^-1 and the total distance traveled is 720m .