Question

PROBLEM 14. Molecular weight of a gas is 80. What will be the
volume of the gas at 23°C and 740 mm pressure ?​

Answer 1

Answer:

PV = n RT

n = number of moles = mass / (mass per mole) = mass / molecular weight = mass / 80

v =?

t = 23+273

p = 740 / 760

R = 8.3

each mole of a gas at STP will be equal to 22. 4 litres

Explanation:

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Answer 2

Answer:

24.95l

Explanation:

n=n.o of moles=1

R=gas constant=0.0821

T=23⁰C=296K

P=740mm=.97atm

Using eq:-PV=NRT

V=24.95l