Question

Problem #2 A photographic "stop bath" contains 160mL of pure acetic acid
HC²H³O², in 650ml solution. What is the v/v concentration of acetic acid
in the stop bath?​

Answer 1

Answer:

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Answer 2

Given:

Contains 160mL of pure acetic acid $HC^{2} H^{3} O^{2}$, in 650ml solution.

To find:

Find the v/v concentration of acetic acid.

Explanation:

Acetic acid=$HC^{2} H^{3} O^{2}$-solute

Volume of acetic acid =160mL

Volume of the solution =650mL

v/v concentration =(solute volume / volume of the solution)*100%

v/v($HC^{2} H^{3} O^{2}$) = $(\frac{160mL}{650mL} )$*100%

=24.6%

Answer:

The v/v concentration of acetic acid is 24.6%.